how do you rotate a figure 90 degrees counterclockwise
90 DEGREE COUNTERCLOCKWISE ROTATION RULE
When we rotate a figure of 90 degrees counterclockwise, each orient of the given figure has to be changed from (x, y) to (-y, x) and graph the rotated human body.
Example 1 :
Let F (-4, -2), G (-2, -2) and H (-3, 1) atomic number 4 the three vertices of a trigon. If this triangle is rotated 90° counterclockwise, find the vertices of the rotated enter and chart.
Solution :
Step 1 :
Here, triangle is rotated 90° anticlockwise. So the rule that we have to enforce here is
(x, y) -------> (-y, x)
Step 2 :
Supported on the rule given in step 1, we take up to find the vertices of the rotated cipher.
Step 3 :
(x , y) -----> (-y , x)
F(-4 , -2) -------> F'(2, -4)
G(-2, -2) -------> G'(2, -2)
H (-3, 1) -------> H'(-1, -3)
Step 4 :
Vertices of the rotated fancy are
F'(2, -4), G'(2, -2) and H'(-1, -3)
Example 2 :
Let A (-4, 3), B (-4, 1), C (-3, 0), D (0, 2) and E (-3,4) be the vertices of a nonopening figure.If this figure is rotated 90 ° counterclockwise, find the vertices of the rotated figure and graph.
Solution :
Measure 1 :
Here, trigon is rotated 90° levorotary. So the rein that we have to apply Here is
(x, y) -------> (-y, x)
Step 2 :
Based on the rule granted in step 1, we have to find the vertices of the turned figure.
Step 3 :
(x, y) -----> (-y, x)
A(-4, 3) -------> A'( -3, -4)
B(-4, 1) -------> B'(-1, -4)
C(-3, 0) -------> C'(0, -3)
D(0, 2) -------> D'(-2, 0)
E(-3, 4) -------> E'(-4, -3)
Step 4 :
Vertices of the rotated figure are
A'(-3, -4), B'(-1, -4), C'(0, -3), D'(-2, 0) and E'(-4, -3)
Example 3 :
Let D (-1, 2), E (-5, -1) and F (1, -1) be the vertices of a trilateral.If the triangle is rotated 90° counterclockwise, find the vertices of the turned figure and graphical record.
Solution :
Step 1 :
Here, triangle is rotated 90° counterclockwise. So the rule that we cause to apply here is
(x, y) -------> (-y, x)
Step 2 :
Based on the rule given in step 1, we make to find the vertices of the rotated enter.
Whole tone 3 :
(x, y) -----> (-y, x)
D(-1, 2) -------> D'(-2, -1)
E(-5, -1) -------> E'(1, -5)
F(1, -1) -------> F'(1, 1)
Step 4 :
Vertices of the rotated figure are
D'(-2, -1) , E'(1, -5) and F'(1, 1)
Object lesson 4 :
Let A (-5, 3), B (-4, 1), C (-2, 1) D (-1, 3) and E (-3, 4) be the vertices of a closed figure.If this figure is rotated 90° counterclockwise, find the vertices of the rotated figure and graph.
Resolution :
Step 1 :
Here, trigon is rotated 90° anticlockwise. And then the rule that we have to apply here is
(x, y) -------> (-y, x)
Step 2 :
Supported on the rule given in step 1, we have to find the vertices of the rotated figure.
Step 3 :
(x, y) -----> (-y, x)
A(-5, 3) -------> A'(-3, -5)
B(-4, 1) -------> B'(-1, -4)
C(-2, 1) -------> C'(-1, -2)
D(-1, 3) -------> D'(-3, -1)
E(-3, 4) -------> E'(-4, -3)
Step 4 :
Vertices of the rotated figure are
A'(-3, -5), B'(-1, -4), C'(-1, -2), D'(-3, -1) and E'(-4, -3)
Object lesson 5 :
Let R (-2, 4), S (-4, 4), T (-5, 3) U (-4, 2) and V (-2, 2) be the vertices of a closed figure.If this figure is rotated 90° left-handed, witness the vertices of the rotated figure and graph.
Solution :
Pace 1 :
Here, triangle is rotated 90° counterclockwise. So the rule that we have to lend oneself here is
(x, y) -------> (-y, x)
Stone's throw 2 :
Based on the rule given in step 1, we give birth to find the vertices of the rotated cipher
Step 3 :
(x, y) -----> (-y, x)
R(-2, 4) -------> R'(-4, -2)
S(-4, 4) -------> S'(-4, -4)
T(-5, 3) -------> T'(-3, -5)
U(-4, 2) -------> U'(-2, -4)
V(-2, 2) -------> V'(-2, -2)
Footstep 4 :
Vertices of the rotated figure are
R'(-4, -2), S'(-4, -4), T'(-3, -5), U'(-2, -4) and E'(-2, -2)
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how do you rotate a figure 90 degrees counterclockwise
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